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• Question: matlab solve 2 equations 2 unknowns
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### matlab solve 2 equations 2 unknowns

To solve a system of 2 equations with 2 unknowns using MATLAB, you can use the built-in function `solve`.

Here’s an example of how to use it:

Suppose we have the following system of equations:

``````3x + 2y = 8
2x - 5y = -13
``````

To solve for `x` and `y`, we can write the equations in MATLAB code as follows:

```makefile```syms x y

eqn1 = 3*x + 2*y == 8;
eqn2 = 2*x - 5*y == -13;

sol = solve([eqn1, eqn2], [x, y]);
``````

The `syms` command is used to create symbolic variables `x` and `y`.

Then we define `eqn1` and `eqn2` as the two equations of the system.

Finally, we use the `solve` function to solve the system, passing in the equations as the first argument and the variables we want to solve for as the second argument. The output will be a structure containing the values of `x` and `y` that satisfy the equations:

```yaml```sol =

struct with fields:

x: 17/11
y: 10/11
``````

So the solution to the system is `x = 17/11` and `y = 10/11`.

### Watch videos related to “matlab solve 2 equations 2 unknowns”

How to Solve Simultaneous Equations in MatLAB Using linsolve and solve

### Can I solve 2 unknowns with 2 equations?

Yes, you can solve for 2 unknowns with 2 equations if the equations are independent, meaning that they provide different information about the unknowns.

For example, consider the system of equations:

x + y = 5
2x – y = 3

This is a system of two equations in two unknowns. You can solve for x and y by using any of the common methods for solving systems of equations, such as substitution or elimination.

Using elimination, you can eliminate y by multiplying the first equation by 2 and subtracting the second equation:

## 2x + 2y = 10 2x – y = 3

3y = 7

So, y = 7/3. Substituting this value into the first equation, you get:

x + 7/3 = 5

Solving for x, you get:

x = 8/3

Therefore, the solution to the system of equations is:

x = 8/3 and y = 7/3.

### How to solve 2 linear equations with 2 variables in matlab?

To solve a system of two linear equations with two variables in MATLAB, you can use the built-in function `linsolve`. Here is an example of how to use `linsolve`:

```matlab```% Define the coefficients of the equations
A = [2 3; 4 5]; % coefficient matrix
b = [8; 14]; % constant vector

% Solve the system of equations
x = linsolve(A, b)

% Display the solution
fprintf('The solution is x = %f, y = %f\n', x(1), x(2))
``````

In this example, the system of equations is:

``````2x + 3y = 8
4x + 5y = 14
``````

The coefficient matrix `A` contains the coefficients of the variables `x` and `y`, and the constant vector `b` contains the constants on the right-hand side of each equation. The `linsolve` function solves the system of equations and returns the values of `x` and `y`. Finally, the solution is displayed using `fprintf`.

### How to combine two equations in Matlab?

In Matlab, you can combine two equations using the following steps:

1. Define the two equations using symbolic variables. For example, suppose you have two equations:

```makefile```syms x y
eqn1 = x + 2*y == 5;
eqn2 = x - y == 1;
``````
2. Use the “solve” function to solve the system of equations. This will give you a solution for both “x” and “y” that satisfy both equations.

```css```sol = solve([eqn1, eqn2], [x, y]);
``````
3. You can then display the solution using the “disp” function:

```java```disp(['x = ', char(sol.x)]);
disp(['y = ', char(sol.y)]);
``````

Note that if the equations have multiple solutions, the “solve” function will return all possible solutions. In this case, you can loop through the solutions to display them all.

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### solve 2 equations 2 unknowns calculator

There are different methods to solve a system of two equations with two unknowns, such as substitution, elimination, or graphing. Here’s how to solve the system using the substitution method:

Example system:

``````2x + 3y = 7
x - 2y = -4
``````
1. Solve one of the equations for one of the variables in terms of the other variable. Let’s solve the second equation for x:
```makefile```x - 2y = -4
x = 2y - 4
``````
1. Substitute the expression you found for x into the other equation, and solve for the remaining variable. Let’s substitute `x = 2y - 4` into the first equation:
```makefile```2x + 3y = 7
2(2y - 4) + 3y = 7
4y - 8 + 3y = 7
7y = 15
y = 15/7
``````
1. Substitute the value you found for the remaining variable into one of the original equations, and solve for the other variable. Let’s use the first equation:
```makefile```2x + 3y = 7
2x + 3(15/7) = 7
2x = 7 - 45/7
2x = 14/7 - 45/7
2x = -31/7
x = -31/14
``````

So the solution to the system is `x = -31/14` and `y = 15/7`.

### matlab solve system of equations

To solve a system of equations in MATLAB, you can use the “solve” function. Here’s an example of how to use it:

Suppose you have the following system of equations:

x + 2y – 3z = 1
3x – y + 2z = 7
2x + y + z = 4

To solve this system, you can define the coefficients of the variables in a matrix and the constants in a column vector:

A = [1, 2, -3; 3, -1, 2; 2, 1, 1];
B = [1; 7; 4];

Then, you can use the “solve” function to obtain the solutions:

X = solve(A*B)

The output will be a structure that contains the values of the variables:

X =

```makefile```x: 1
y: 2
z: -1
``````

This means that the solution to the system of equations is x=1, y=2, and z=-1.

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